求复合函数的高阶导数We are given a function f(x) = (x^2 - 3x + 2)^(n)

Not sure about cos(x^2), will take a look later. For the other, there is, I think it's: Please verify, where P for permutation, C for combination. ------------ yes, should be n-m+i, instead of n-m-i

there should be a general formula for v(x) also. I thought about a little, but only got partial results. I don't think I'll have much time until the weekend to think again. Here's what I have for nth-order derivative: 1. if n is odd, it has (n+1)/2 terms, which have x, x^3, ..., x^n (along with sin(x^2) or cos(x^2)). The term containing x^n can be expressed in (-1)^((n+1)/2)*(2x)^n*sin(x^2). The others are the sum of something related to n (you can try to find yourself). 2. if n is even, it has n/2 terms, which have x, x^3, ..., x^n (along with sin(x^2) or cos(x^2)). The term with x^n can be expressed in (-1)^(n/2)*(2x)^n*cos(x^2). The co-efficient of the others are the sum of something related to n).