英文奥林匹克数学题！1.The digits of a 2-digit number are the same.When
英文奥林匹克数学题！
1.The digits of a 2-digit number are the same.When you multiply this number by 99, you get a 4-digit number in which the third digit (the number of tens) is 5. What number did you get after the multiplication?
2.In a running race there were 12 racers marked with numbers. What was their order at the finish line if, for every racer, the product of the racing number and the place-number the runner finished at was one more than a number divisble by 13?
翻译+答案
1.The digits of a 2-digit number are the same.When you multiply this number by 99, you get a 4-digit number in which the third digit (the number of tens) is 5. What number did you get after the multiplication?
2.In a running race there were 12 racers marked with numbers. What was their order at the finish line if, for every racer, the product of the racing number and the place-number the runner finished at was one more than a number divisble by 13?
翻译+答案
赞 安安V乐乐 幼苗
共回答了17个问题采纳率：100% 举报
1.一个个位和十位数字相同的两位数，当你将其乘以99时，你得到一个十位为5的四位数。请问乘出的数是多少？ 很简单啊。穷举就可以了。最后原两位数为44，乘出的数为4356。 2.一场跑步赛有12位选手标有不同的号码。到达终点时，如果他们的号码和他们的名次满足这样的关系：对每一位选手，他的号码和名次成绩乘积都比一个13的倍数大1，那么他们各自的名次应该是多少？ 翻译过来就简单了嘛。显然应该是（从1号到12号分别是）：1，7，9，10，8，11，2，5，3，4，6，12 第二题附vb穷举的程序 对于答案的唯一性，数学上有严格证明，就不在此赘述了 祝你答得开心~ vb程序： For i = 1 To 12 For j = 1 To 12 If i * j Mod 13 = 1 Then Text1 = Text1 & "," & Str$(j) & " " Next Next
1年前
6
共回答了16个问题采纳率：87.5% 举报
1.一个个十位相同的两位数*99以后的一个四位数，其十位为5，则这个四位数是多少？ 答案：4356=44*99 2.在一个按顺序编号的12名赛跑手比赛中，若对于每名赛跑手来说，他在终点处取得的名次与其自己的编号相乘所得除以13后均余1，求赛跑手们对应的名次？ 答案： 加分给答案...
1年前
1
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