魅惑狂狷地一笑 幼苗
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设需要98%H2SO4的体积为VmL,
根据溶液稀释前后溶质质量不变则,
VmL×1.84g/mL×98%=500mL×1.14g/mL×20%
解得:V=63.2mL
需要水的质量为:500mL×1.14g/mL-63.2mL×1.84g/mL=453.7g,需要水的体积为453.7mL
答:浓H2SO4及水的体积分别是63.2mL,453.7mL.
点评:
本题考点: 有关溶质质量分数的简单计算.
考点点评: 本题考查溶液的稀释计算,学生应把握溶液稀释前后溶质的质量不变并能利用溶液中溶质的质量分数来进行相关的计算.
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