(1) f(x)= e x x ,∴ f′(x)= e x (x-1) x 2 . 当x∈(0,1)时,∴f(x)在(0,1]上递减; 当x∈(1,+∞)时,∴f(x)在[1,+∞)上递增. ∴当m≥1时,f(x)在[m,m+1]上递增, f(x ) min =f(m)= e m m ; 当0<m<1时,f(x)在[m,1]上递减,在[1,m+1]上递增,f(x) min =f(1)=e. ∴ f(x ) min =
e m m ,m≥1 e,0<m<1 . (2)∀x>0,e x >-x 2 +λx-1恒成立,即 λ< e x x +x+ 1 x 恒成立. 由(1)可知, ∀x>0, e x x ≥e ,当且仅当x=1时取等号, 又 ∀x>0,x+ 1 x ≥2 ,当且仅当x=1时取等号, ∴当且仅当x=1时,有 ( e x x +x+ 1 x ) min =e+2 . ∴λ<e+2.