zjb030335
幼苗
共回答了26个问题采纳率:84.6% 举报
√12-√18+√0.5+√(1/3)
=2√3-3√2+√2/2+√3/3
=7√3/3-5√2/2
[√72+√2/(2+√3)]*√3-7√6
=[6√2+√2(2-√3)/(2+√3)(2-√3)]*√3-7√6
=[6√2+2√2-√6]*√3-7√6
=(8√2-√6)*√3-7√6
=8√6-3√2-7√6
=√6-3√2
√[(x^2+9)/3x+2]+√[(x^2+9)/3x-2]
=√[(x^2+6x+9)/3x]+√[(x^2-6x+9)/3x]
=√(x+3)^2/3x+√[(x-3)^2/3x]
=(x+3)√(1/3x)+(3-x)√(1/3x)
=6/[1/√(3x)]
=6*√(3x)
=6√(3x)
(2√3+3√2-√6))*(2√3-3√2+√6)
=(2√3+3√2-√6))*[2√3-(3√2-√6)]
=(2√3)^2-(3√2-√6)^2
=12-(18+6-6√6*√2)
=12-(24-12√3)
=12√3-12
1年前
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