ggback 幼苗
共回答了22个问题采纳率:86.4% 举报
1年前
thomsonfawn 幼苗
共回答了93个问题 举报
回答问题
1/2xy-{1/2xy-[1/3x^2y-(x^2y-xy)]+1/3x^2y}
1年前1个回答
[(3x+2y)^2-(3x+2y)^2+3x^2y^2]/2xy=
已知|x|=3,|y|=2,求3x^2y-[2xy^2-2(3x^2y+2xy^2)]
求代数式2x^2y+{2xy-[3x^2y-2(-3x^2y+2xy)]-4xy^2},其中x=-1/2 y=2
1年前3个回答
计算(2 x^3-3x^2y-2xy^2)-(x^3-2xy^2)-(x^3+3x^2y)的值,
(2x3-3x2y-2xy2)-(x3-2xy2+y3)+(-x3+3x2y-y3)
化简:[(-2xy^2)^3*(-3x^2y^3)+(-2xy^2)^2*(3x^2y^3)^2*xy^2]/(x^5y
(-1/3x^2y)(2xy-3x^2y^2-5)
【(3x-2y)的平方-(3x+2y)的平方】/(2xy)
计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
计算(2x^3-3x^2y-2xy^2)-(x^3-2xy^2+y^3)+(-x^3+3x^2y-y^3)
1年前2个回答
1/3X平方_2Y立方_2XY平方+2Y立方+2XY平方+5+2/3X平方,其中(X-2Y)平方+Y_1的绝对值=0
(2x^3-3X^2Y-2XY^2)-(X^3-2XY^2+Y^3)+(-X^3+3X^2Y-Y^3)求解法
2x^2y+{2xy-[3x^2y-2(-3xy2+2xy)]-4xy^2}
3xy^2-2xy-二分之三x^2y+(3x^2y-2xy^2)
(1)化简:3x2y-[2xy-(xy-[3/2]x2y+2xy)]
来哥们,先化简,后求值!(2x^2y-2xy^2)-[(-3x^2y^2+3x^2y)+(3x^2y^2-3xy^2],
(3x^2y^3)/(2xy)^2=?(3x^2y^2)/(xy)*(1/y)=?x^2y-5x^2y+3x^y=?(6
(2x^2y-2xy^2)-[(-3x^2y^2+3x^2y)+(3x^2y^2-3xy^2)]其中x=-1,y=2
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读“南纬22°地形剖面图”,回答下列问题。
They are still very cautious about ________ side effect the new medicine will bring about, although the experts have tried it on about 2000 patients.
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2乘x减1的绝对值等于根号5,求x