找个人恋爱 幼苗
共回答了12个问题采纳率:91.7% 举报
两铜环都处于静止时,受力都平衡,对右侧铜环研究得知,铜环竖直方向要平衡,绳子不能与BC平行,绳子应斜向左上,则有θ>β.对左侧铜环研究得知,铜环在AB方向上受力要平衡,绳子不能与AB垂直,即有θ<[π/2],则得到θ的范围为β<θ<
π
2.
故选D
点评:
本题考点: 共点力平衡的条件及其应用;力的合成与分解的运用.
考点点评: 本题是两个物体的平衡问题,采用的是隔离法的思想,根据平衡条件分析得到θ的范围.
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