怎么证明tan^2A+cot^2A不等于1

wyhjysjys 1年前 已收到1个回答 举报

xxx1922192 幼苗

共回答了21个问题采纳率:81% 举报

tan^2A+cot^2A
=sin^2A/cos^2A+cos^2A/sin^2A
=sin^4A+cos42A/sin^2A*cos^2A
=sin^4A+cos42A/(1/4*sin^22A)
=4*sin^4A+4*cos42A/sin^22A
=[4*sin^4A-4*sin^2A+1+4*cos^4A-4*cos^2A+1+4*sin^2A+4cos^2A-1-1]/sin^22A
=[(1-2*sin^2A)^2+(2*cos^2A-1)^2+4*(sin^2A+cos^2A)-2]/sin^22A
=[cos^22A+cos^22A+4-2]/sin^22A
=[2cos^22A+2]/sin^22A
因为:2cos^22A+2>=2,sin^22A

1年前

9
可能相似的问题
Copyright © 2024 YULUCN.COM - 雨露学习互助 - 16 q. 0.023 s. - webmaster@yulucn.com