taiyang200000
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如果给你个例子:x/1!-(x^3)/3!+(x^5)/5!.....(-1)^(n-1)*(x^(2n-1))/(2n-1)! #include #include main() { float sum,term,x; int n,k,sign; printf("Input n,x:n"); scanf("%d%f",&n,&x); sum=x; term=x; sign=1; for(k=2;k<=n;k++) { term*=x*x/(2*k-2)/(x*k-1); sign=-sign; sum+=sign*term; } printf("sum=%fn",sum) } 怎么改成我的问题答案呢?