利用VB如何设计下面问题:利用随机数产生10个1~100之间的随机数,显示出最大值,最小值及平均值.

TTYYKK 1年前 已收到1个回答 举报

云在西安 幼苗

共回答了15个问题采纳率:86.7% 举报

Private Sub Form_click()
Dim a(9)
Dim m(),n() 'm()为偶数集,n()为奇数集
Dim i,p,q
Dim sum
Dim avg1,avg2 'avg1为奇数平均数,avg2为偶数平均数
Dim max,min
For i = 0 To 9
Randomize
a(i) = Int(Rnd() * 99 + 1)
If a(i) Mod 2 = 0 Then '判断偶数,是,将存入偶数集
p = p + 1
ReDim Preserve m(p)
m(p) = a(i)
Else '不是,将存入奇数集
q = q + 1
ReDim Preserve n(q)
n(q) = a(i)
End If
Next i
max = a(0) '最大值最小值
min = a(0)
For i = 1 To 9
If a(i) > max Then max = a(i)
If a(i) < min Then min = a(i)
Next i
Print "10个数中的最大值为" & max
Print "10个数中的最小值为" & min
For p = LBound(m()) To UBound(m())
sum = sum + m(p)
Next p
avg2 = sum / UBound(m())
Print "10个数中偶数之平均数为" & avg2
sum = 0
For q = LBound(n()) To UBound(n())
sum = sum + n(q)
Next q
avg1 = sum / UBound(n())
Print "10个数中奇数之平均数为" & avg1
End Su

1年前

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