ququ32
幼苗
共回答了16个问题采纳率:93.8% 举报
f(x) = 1/[2^x + 2^(1/2)],
f(1-x) = 1/[2^(1-x) + 2^(1/2)] = 2^x/[2 + 2^(1/2 + x)] 分子分母同乘2^x
= 2^(x-1/2)[2^x + 2^(1/2)] 分子分母同除2^(1/2)
f(x) + f(1-x) = [1 + 2^(x-1/2)]/[2^x + 2^(1/2)]
= 2^(-1/2)[ 2^x + 2^(1/2)]/[2^x + 2^(1/2)] 分子提出2^(-1/2)因子
= 2^(-1/2)
= 1/2^(1/2)
不等于1哈,但思路应该是一样的.
1年前
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