牵手望水
幼苗
共回答了20个问题采纳率:90% 举报
(1)1/2x-1/(x+y)*[(x+y)/2x-x-y]
=1/2x-1/(x+y)*[(x+y)/2x-2x(x+y)/2x]
=1/2x-1/(x+y)*[(x+y)-2x(x+y)]/2x
=1/2x-1/(x+y)*(x+y)(1-2x)/2x
=1/2x-(1-2x)/2x
=[1-(1-2x)]/2x
=2x/2x
=1
(2)[1/(m+n)²-1/(m-n)²]÷[(1/(m+n)-1/(m-n)]
=[(m-n)²-(m+n)²]/[(m+n)²*(m-n)²]÷[(m-n)-(m+n)]/[(m+n)(m-n)]
=-4mn/[(m+n)²*(m-n)²]÷(-2n)/[(m+n)(m-n)]
=-4mn/[(m+n)²*(m-n)²]*[(m+n)(m-n)]/(-2n)
=2m/[(m+n)(m-n)]
=2m/(m²-n²)
(3){2/3x-2/(x+y)*[(x+y)/3x-x-y]}÷(x-y)/y
={2/3x-2/(x+y)*[(x+y)(1-3x)/3x]}÷(x-y)/y
={2/3x-2(1-3x)/3x}*y/(x-y)
=[2-2(1-3x)]/3x*y/(x-y)
=6x/3x*y/(x-y)
=2y/(x-y)
1年前
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