a | 2 n−1 |
saer223 幼苗
共回答了23个问题采纳率:91.3% 举报
1 |
n2 |
a | 2 n−1 |
1 |
n2 |
a | 2 n−1 |
1 |
n2 |
n2 |
n2+n−1 |
1 |
an−1 |
1 |
an |
1 |
n2+n−1 |
1 |
n(n+1) |
1/n |
1 |
n+1],[1 |
a1 |
1 |
an |
1/2 |
1 | ||
n+1],而a1=
| ||
an |
5/6 |
1 |
n+1 |
1 |
n+1 |
n+2 | ||
n+1],∴a n>
(1)∵a0= 点评: 1年前
1
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