201fanpengjx
幼苗
共回答了13个问题采纳率:92.3% 举报
同时掷两个色子,每个色子出现 1-6 点为 1/6
两个色子点数和为 2-12,其概率分别为:
p2 = 1*1/6*1/6 = 1/36
p3 = 2*1/6*1/6 = 1/18
p4 = 3*1/6*1/6 = 1/12
p5 = 4*1/6*1/6 = 1/9
p6 = 5*1/6*1/6 = 5/36
p7 = 6*1/6*1/6 = 1/6
p8 = 5*1/6*1/6 = 5/36
p9 = 4*1/6*1/6 = 1/9
p10 = 3*1/6*1/6 = 1/12
p11 = 2*1/6*1/6 = 1/18
p12 = 1*1/6*1/6 = 1/36
这玩意儿好像叫作“泊松分布”……
1年前
11