HF人在BJ
幼苗
共回答了17个问题采纳率:76.5% 举报
1,f(x)=sin[(π/2)x+π/6]-2[sin(π/4)x]^2
=(√3/2)sin(π/2)x+(1/2)cos(π/2)x+cos(π/2)x-1
=√3sin[(π/2)x+π/3]-1
f(x)的最小正周期为T=(2π)/(π/2)=4.
2,-g(x)=√3sin[(π/2)(-x)+π/3]-1=-√3sin[(π/2)x-π/3]-1,g(x)=√3sin[(π/2)x-π/3]+1.
g(1)=√3sin[π/2-π/3]+1=√3/2+1,g(2)=√3sin[π-π/3]+1=3/2+1,
g(3)=√3sin[3π/2-π/3]+1=-√3/2+1,g(4)=√3sin[2π-π/3]+1=-3/2+1
g(1)+g(2)+g(3)+g(4)=4
g(1)+g(2)+g(3)+g(4)+…+g(2012)=503*[g(1)+g(2)+g(3)+g(4)]=503*4=2012
1年前
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