gozillakat 幼苗
共回答了16个问题采纳率:93.8% 举报
data = { {0,0}, {0.15,0.072}, {0.25,0.119}, {0.5,0.243}, {1.0,0.494}, {1.5,0.618}, {2.0,0.831}, {2.5,0.999} };
f = Fit[ data, {1,x}, x ];
lp = ListPlot[ data ];
p = Plot[ f, {x,-0.5,3} ];
Show[ lp,p ]
运行即可.
其中f即为所求直线,解析式为
f = 0.0277774 + 0.399213 x
图如下:
(baidu默认200x200像素,不知道能不能看清楚)
1年前
你能帮帮他们吗