初二数一元二次方程,怎样解答?

2(x-5)²=3(x-5)
2(x-5)²-3(x-5)=0
(x-5)[2(x-5)-3]=0
(x-5)(2x-13)=0
x=5或x=13/2
4x²-121=0
4x²=121
2x=±11
x=±11/2
即：x=11/2或x=-11/2
3x²-6x=0
3x(x-2)=0
x=0或x=2
8x²-3x=0
x(8x-3)=0
x=0或x=3/8
3x(2x+1)=4x+2
6x²+3x-4x-2=0
6x²-x-2=0
(2x+1)(3x-2)=0
x=-1/2或x=2/3
2x+6=（x+3)²
（x+3)²-2(x+3)=0
(x+3)(x+3-2)=0
(x+3)(x+1)=0
x=-3或x=-1