平面向量题目一道..在三角形ABC中 D为BC上一点,P为AD上一点 且满足(向量)AP=5/13(向量)AB+4/13
平面向量题目一道..
在三角形ABC中 D为BC上一点,P为AD上一点 且满足(向量)AP=5/13(向量)AB+4/13(向量)AC,试求(模长)BD:CD
4 思路.
在三角形ABC中 D为BC上一点,P为AD上一点 且满足(向量)AP=5/13(向量)AB+4/13(向量)AC,试求(模长)BD:CD
4 思路.
赞
共回答了1627个问题 举报
AP=(5/13)AB+(4/13)AC
D is on BC
let: BD = kBC ( k is a constant )
P is on AD
let |AP|/|PD| = m
BP = (BA+ mBD)/(1+m)
BA+AP = (BA+ mBD)/(1+m)
AP = [m/(1+m)]AB + (m/(...
D is on BC
let: BD = kBC ( k is a constant )
P is on AD
let |AP|/|PD| = m
BP = (BA+ mBD)/(1+m)
BA+AP = (BA+ mBD)/(1+m)
AP = [m/(1+m)]AB + (m/(...
1年前
2
可能相似的问题
你能帮帮他们吗