geckoegg
幼苗
共回答了11个问题采纳率:72.7% 举报
设A有酒精x克,B有酒精(y+3)克,C有酒精y克
因为A中有酒精40%x
B中有酒精36%(y+3)
C中有酒精35%y
所以40%x+36%(y+3)+35%y=38.5%(x+y+3+y)
40%x+36%y+36%*3+35%y=38.5%x+38.5%(y+3)+38.5%y
40%x+36%y+108%+35%y=38.5%x+38.5%y+38.5%*3+38.5%y
40%x+71%y+108%=38.5%x+77%y+115.5%
71%y+108%-77%y=38.5%x-40%x+115.5%
-6%y+108%=-1.5%x+115.5%
1.5%x=6%y+115.5%-108%
1.5%x=6%y+7.5%
1.5%x=6%y+40分之3
200分之3x=50分之3y+40分之3
又x+y+y+3=11
2y+x=11-3
2y+x=8
x=8-2y
即200分之3x=50分之3y+40分之3
=200分之3(8-2y)=50分之3y+40分之3
1.5%(8-2y)=6%y+7.5%
12%-3%y=6%y+7.5%
12%-7.5%=6%y+3%y
4.5%=9%y
y=4.5%/9%
y=4.5/9
y=0.5
A种酒精有11-0.5-3-0.5
=7(千克)
1年前
9