化简求值:2x^3·y^2[xy(1-x)-2x(y-1/2)]2x^4·y^3(x+1),其中x^2·y=-1/4

答：楼主,你的题目有问题啊.请检查后追问,
2x^3·y^2[xy(1-x)-2x(y-1/2)]2x^4·y^3(x+1),其中x^2·y=-1/4
原式
=2x³y²*[xy(1-x)-2x(y-1/2)]*(2x^4)*y³(x+1)
=2(x²y)(xy)*[xy-x²y-2xy+x]*2(x²y)²(yx+y)
=4*(-1/4)*(xy)(-x²y-xy+x)*(-1/4)²*(yx+y)
=(-1/16)*(x²y)(-xy-y+1)*(yx+y)
=(-1/16)*(-1/4)*(-x²y²-xy²-xy²-y²+xy+y)
=(1/64)*(-y/4-2xy²-y²+xy+y)
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