9 8 7 6 5 4 3 2 1+=1000 写上加减符号使算式成立.谁会?

计算机编程所得：
987+6+5+4-3+2-1
987+6+5-4+3+2+1
987-6+5-4-3+21
#include
#include
#define LEN 18
//0没有符号
//1减号
//2加号
void main(void)
{
x05int i;
x05int j = 0;
x05int k,g;
x05int sum;
x05int data[9];
x05int fu[8] = { 0 };
x05long n = 1000000;
x05char ch = '9';
x05char array[LEN] = { '' };
x05char num[9][4];
x05printf("resultn");
x05for (i=0; i k)
x05x05x05{
x05x05x05x05fu[g++] = array[i];
x05x05x05x05num[j][k++] = '';
x05x05x05x05k = 0;
x05x05x05x05num[++j][k++] = array[i+1];
x05x05x05}
x05x05x05else
x05x05x05{
x05x05x05x05goto MARK;
x05x05x05}x05
x05x05}
x05x05for (i=0; i

987+6+5-4+3-2+1