AP chemistry的一道题目

AP chemistry的一道题目
Step 1:N2H2O2  N2HO2- + H+ (fast equilibrium)
Step 2:N2HO2-  N2O + OH- (slow)
Step 3:H+ + OH-  H2O (fast)
Nitramide,N2H2O2,decomposes slowly in aqueous solution.This decomposition is believed to occur according to the reaction mechanism above.The rate law for the decomposition of nitramide that is consistent with this mechanism is given by which of the following?
(A) Rate= k[N2H2O2]
(B) Rate= k[N2H2O2][H+]
(C) Rate= k[N2H2O2]/[H+]
(D) Rate= k[N2H2O2]/[N2HO2-]
(E) Rate= k[N2H2O2][OH-]
Answer:C
请具体讲一讲为什么选C啊?
眯眼男人 1年前 已收到2个回答 举报

linjing0107 花朵

共回答了16个问题采纳率:93.8% 举报

The rate law is determined in this case by the slowest reaction step:
rate = k[N2HO2-]
Equilibrium for step before the slowest step:
K = [N2HO2-][H+] / [N2H2O2]
K[N2H2O2] / [H+] = [N2HO2-]
rate = k{K[N2H2O2] / [H+]}
rate = (k1)[N2H2O2] / [H+]

1年前

6

小甜甜是我 幼苗

共回答了1个问题 举报

虽然我还在学 GCSE chemistry 但是我觉得应该跟 ionic 或者 covalent bond 有关系吧?
再加上balance equation ? 不会的话我劝你去问老师,希望早日找到满意的答案

1年前

2
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