赞 barajas2008 幼苗
共回答了20个问题采纳率：80% 举报
x100x100(2x-1)^30×(3x-2)^50/(2x+1)^20
x100x100= [(2x-1)/(2x+1)]^30×[(3x-2)/(2x+1)]^20
x100x100= [(2-1/x)/(2+1/x)]^30×[2×(3/2-1/x)/(2+1/x)]^20
x100(当x->∞时,1/x->0)
x100x100= [(2-0)/(2+0)]^30×[2×(3/2-0)/(2+0)]^20
x100x100= 1^30×(3/2)^20
x100x100= (3/2)^20
x100x100= [(2x-1)/(2x+1)]^30×[(3x-2)/(2x+1)]^20
x100x100= [(2-1/x)/(2+1/x)]^30×[2×(3/2-1/x)/(2+1/x)]^20
x100(当x->∞时,1/x->0)
x100x100= [(2-0)/(2+0)]^30×[2×(3/2-0)/(2+0)]^20
x100x100= 1^30×(3/2)^20
x100x100= (3/2)^20
1年前
2
可能相似的问题
-
1年前3个回答
-
1年前1个回答
-
1年前1个回答
你能帮帮他们吗