让ABC ABC分别是的角度A BC三角形两侧M =（COSC / 2,正弦/ 2）,N =（COSC / 2,正弦/
让ABC ABC分别是的角度A BC三角形两侧M =（COSC / 2,正弦/ 2）,N =（COSC / 2,正弦/ 2）,1角C 2已知C = 7/2倍的根三角形= 3/2 A + B的价值
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让载体OM,对模具|
OM |,| | COS∠MON = COS?= 1/2 =（OM *）/（| OM | * | |）OM * = COSC / 2 *
cosC/2-sinC/2 *正弦/ 2 = COSC | OM | = 1,| | = 1 1/2 = COSC,C SINC =√3/2S = 3
*√3/2 =,AB 1/2absinC = 6
OM |,| | COS∠MON = COS?= 1/2 =（OM *）/（| OM | * | |）OM * = COSC / 2 *
cosC/2-sinC/2 *正弦/ 2 = COSC | OM | = 1,| | = 1 1/2 = COSC,C SINC =√3/2S = 3
*√3/2 =,AB 1/2absinC = 6
1年前
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