只能这样看着你
幼苗
共回答了16个问题采纳率:93.8% 举报
y=cosx*(-2)sin[(x+x+2/3)/2]sin[(-2/3)/2]
=2cosxsin(x+1/3)sin(1/3)
=2sin(1/3)cosxsin(x+1/3)
= 2sin(1/3)(1/2)*[sin(2x+1/3)+sin(1/3)]
=sin(1/3)sin(2x+1/3)+sin^2(1/3).
ymax=sin^2(1/3)+sin(1/3);
ymin=sin^(1/3)-sin(1/3).
1年前
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