设集合A＝{y｜y＝x∧2－2x－2,y∈z｝.B＝｛y｜y＝－x∧2＋8x＋2.y∈z｝求A∩B中

A＝{y｜y＝x^2－2x－2,y∈z }
B＝｛y｜y＝－x^2＋8x＋2,y∈z｝
x^2－2x－2=－x^2＋8x＋2
x^2-5x-2=0
x=(5+√33)/2 or (5-√33)/2
x=(5+√33)/2
y= [(5+√33)/2]^2-2[(5+√33)/2]-2
=(29+√33)/2 - (5+√33) -2
= (1/2)(15-√33)
x=(5-√33)/2
y= [(5-√33)/2]^2-2[(5-√33)/2]-2
=(29-√33)/2 - (5-√33) -2
= (1/2)(15+√33)
A∩B ={(1/2)(15+√33) ,(1/2)(15-√33) }