lynnyyll 幼苗
共回答了14个问题采纳率:85.7% 举报
1年前
回答问题
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
1年前2个回答
整体去括号;[5(x-y)-3(x-y)-(x-y)+2(x-y)]-2(x-y)
1年前1个回答
整体去括号;化简[5(x-y)-3(x-y)-(x-y)+2(x-y)]-2(x-y)
5(x-y)的立方-3(x-y)的平方+7(x-y)-3(x-y)的立方+(x-y)的平方-5,x-y=1/3.
1年前3个回答
5(x-y)³-3(x-y)²+7(x-y)-5(x-y)³+(x-y)²-5(
把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)
1年前4个回答
若将x-y看成一个整体,则化简(x-y)^2—3(x-y)-4(x-y)^2+5(x-y)
把(x-y)看作一个整体,化简:(1)5(x-y)+2(x-y)-4(x-y);(2)3(x-y
(x-y)的2次方-2(x-y)+(x-y)-5(x-y)
5(x-y)^2-(x-y)-8(x-y)^2-3(x-y)
几道简单的代数题若多项式2(x-y)^2-7(x-y)^3-5(x-y)^2+(x-y)/7(x-y)^3+3(x-y)
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x-y)²-7(x-y)+8(x-y)²+5(x-y)
如将(x-y)看成一个因式,则合并(x-y)²-3(x-y)-4(x-y)²+5(x-y)的结果是(
化简:3(x-y)²-7(x-y)+ 2(x-y)²+5(x-y)
化简 3(X-Y)²-4(X-Y)+7(X-Y)-6(X-Y)²
把(x-y)作为一个因式,合并同类项:3(x-y)2-9(x-y)-8(x-y)2+6(x-y)-1.
如将(x-y)看成一个因式,则合并(x-y)的平方-(x-y)-4(x-y)的平方+5(x-y)的结果是?
吧(x-y)当做一个因式,合并同类项2(x-y)的平方-7(x-y)+3(x-y)的平方-(x-y)
把x-y,合并同类项:5(x-y)+3(x-y)-7(x-y)=
你能帮帮他们吗
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做匀减速运直线运动的物体经4s后停止,若在第1s内位移是14m,则最后1s的位移是( )
如何求f(x)=f(x-1)+f(x+1)的周期
英语翻译妈妈要求他的孩子马上收拾好他的房间(demand)
精彩回答
下列对文学名著表述有误的一项是 [ ]
在印度民族大起义中导军民与英军展开激战,经常单枪匹马,身先士卒,砍杀敌人,直到壮烈牺牲的是________
把一片新鲜的叶片浸在盛有热水的烧杯中,会看到叶片的表面产生了许多的气泡,而且实验显示叶片背面产生的气泡比正面的多.由此可以说明( )
已知函数f(x)=cos(2x+ϕ)满足f(x)≤f(1)对x∈R恒成立,则( )
初中数学二次函数交点式求法,运用交点式要怎么代入呢?比如已知(1,2)(3.6)怎么代入Y=A(X-X1)(X-X2) 详细点步骤