通分：(1)x/x^2+2x+1,(2)x-1/x^2+x,(3)1/x^2-1

jamen2003 1年前 已收到2个回答 举报
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gthb 花朵

共回答了8个问题采纳率：87.5% 举报

x/(x^2+2x+1)
=x/(x+1)^2
=x^2(x-1)/[x(x+1)^2(x-1)]
=(x^3-x^2)/[x(x+1)^2(x-1)]
(x-1)/(x^2+x)
=(x-1)/[x(x+1)]
=(x-1)^2(x+1)//[x(x+1)^2(x-1)]
=(x^3-x^2-x+1)/[x(x+1)^2(x-1)]
1/(x^2-1)
=1/[(x+1)(x-1)]
=x(x+1)/[x(x+1)^2(x-1)]
=(x^2+x)/[x(x+1)^2(x-1)]

1年前

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刘旋 幼苗

共回答了2060个问题 举报

(1)x/x^2+2x+1=x/(x+1)^2=x^2(x-1)/x(x-1)(x+1)^2
(2)x-1/x^2+x=(x-1)/x(x+1)=(x+1)(x-1)^2/x(x-1)(x+1)^2
(3)1/x^2-1=1/(x^2-1)=1/(x-1)(x+1)=x(x+1)/x(x-1)(x+1)^2

1年前

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