fbmg1159
幼苗
共回答了10个问题采纳率:100% 举报
解法一:图形D的面积=∫(-2,4)(y+4-y²/2)dy
=(y²/2+4y-y³/6)│(-2,4)
=4²/2+4*4-4³/6-(-2)²/2-4*(-2)+(-2)³/6
=18
解法二:图形D的面积=∫(0,2)2√(2x)dx+∫(2,8)[√(2x)-x+4]dx
=[(4√2/3)x^(3/2)]│(0,2)+[(2√2/3)x^(3/2)-x²/2+4x]│(2,8)
=16/3++64/3-32+32-8/3+2-8
=18
1年前
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