7209
幼苗
共回答了26个问题采纳率:96.2% 举报
A01 = 0
A02 = 4
A03 = 8
.....
A11 = 20
A12 = 24
....
所以按行存储的公式是Aij = 20*i+4*(j-1)
所以B = A35 = 20*3+4*(5-1) = 60+16 = 76
C = A53 = 20*5+4*(3-1) = 100+8 = 108
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下面是按列存储
A01 = 0
A11 = 4
A21 = 8
......
A11 = 36
A12 = 40
.......
所以按列存储的公式是Aij = 4*i + 36*(y-1)
所以D = A71 = 4*7 + 36*(1-1) = 28
E = A24 = 4*2 + 36*(4 -1)= 8+36*3 = 116
A的地址无论是按行存储还是按列存储都一样的,
行存储:A85 = 20*8 + 4*(5-1) = 160+16 = 176
列存储:A85 = 4*8 + 36*(5-1)=32 + 144 = 176
所以答案是176,76,108,28,116
1年前
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