不通过求值,比较下列各组中两个三角函数值的大小sin(-53π/7)与sin(-59π/8),cos500°与cos53

不通过求值,比较下列各组中两个三角函数值的大小sin(-53π/7)与sin(-59π/8),cos500°与cos530°
一个人下棋 1年前 已收到3个回答 举报

cmccindy 春芽

共回答了15个问题采纳率:93.3% 举报

∵sin(-53π/7)=sin(-8π+3π/7)
=sin(π/2-π/14)
=cos(π/14)
sin(-59π/8)=sin(-8π+5π/8)
=sin(π/2+π/8)
=cos(π/8)
又∵cosx在x∈[0,π]上是减函数,
而π/14cosπ/8
∴sin(-53π/7)>sin(-59π/8)
∵cos500°=cos(360°+90°+50°)
=cos(90°+50°)
=-sin50°
cos530°=cos(2×360°-170°)
=cos170°
=cos(90°+80°)
=-sin80°
又∵sin80°>sin50°
∴-sin80°cos530°

1年前

4

psdcool 幼苗

共回答了4个问题 举报

sin(-53π/7)=sin(3π/7) sin(-59π/8)= sin(5π/8)
所以sin(-53π/7)大于sin(-59π/8)
cos500°=-sin50°,cos530°=-sin80°
-sin80°<-sin50°
∴cos500°>cos530°

1年前

1

kyj12320000 幼苗

共回答了1个问题 举报

sin(-53π/7)=sin(3π/7) sin(-59π/8)= sin(5π/8)
sin(5π/8) = sin(3π/8) 小于sin(3π/7)
所以sin(-53π/7)大于sin(-59π/8)
,cos500°与cos530°(同理)

1年前

0
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