请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)

sin(x+π/2)=cos x
cos(x+π/2)=-sinx
tan(x+π/2)=sin(x+π/2)÷cos(x+π/2)=cos x÷(-sinx) = -cotx
cot(x+π/2)=1÷tan(x+π/2)=1÷（-cotx）= - tan x
sec(x+π/2)=1÷cos(x+π/2)=1÷(-sinx)=(-1/sinx)
csc(x+π/2)=1÷sin(x+π/2)=1÷(cos x)=1/cosx
sin(x+π)=-sinx
cos(x+π)=-cosx
tan(x+π)=sin(x+π)÷cos(x+π)=（-sinx）÷（-cosx）=tan x
cot(x+π)=1÷tan(x+π)=1÷tan x = cot x
sec(x+π)=1÷cos(x+π)=1÷(-cosx)=(-1/cos x)
csc(x+π)=1÷sin(x+π)=1÷(-sinx)=(-1/sin x)

sin(x+π/2)=cosx cos(x+π/2)=-sinx

sin(x+π)=-sinx,cos(x+π)=-cosx,tan(x+π)=sin(x+π)÷cos(x+π)=（-sinx）÷（-cosx）=tan x,cot(x+π)= cot x,sec(x+π)=1÷cos(x+π)=1÷(-cosx)=(-1/cos x),csc(x+π)=1÷sin(x+π)=1÷(-sinx)=(-1/sin x)
不懂详细看一下高中数学课本，会有的！