mandy_cy
幼苗
共回答了19个问题采纳率:89.5% 举报
为隐函数微分
1)y=x+e^y
dy=dx+e^ydy
dy/dx=1/(1-e^y)
2)y=cos(xy)-x
dy=-sin(xy)(ydx+xdy)-dx
dy=-[sin(xy)*y+1]dx-sin(xy)*xdy
[1+xsin(xy)]dy=-[ysin(xy)+1]dx
dy/dx=-[ysin(xy)+1]/[xsin(xy)+1]
1年前
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第二题和答案一样,第一题答案上写的是dy/dx=e^y/1-xe^y答案错了?