bsyuxkllxl
幼苗
共回答了22个问题采纳率:90.9% 举报
原式=(x^2+y^2)+(z^2+1)^2+8xyz-4x^2y^2-2x^2z^2-2y^2z^2-2x^2-2y^2-4z^2 =(x^2+y^2)+(z^2+1)^2+8xyz-2z^2(x^2+y^2)-2(x^2+y^2)-4x^2y^2-4z^2 =(x^2+y^2)+(z^2+1)^2-2(z^2+1)(x^2+y^2)+4(2xyz-x^2y^2-z^2) =[(x^2+y^2)-(z^2+1)]^2-[2(xy-z)]^2 =(x^2+y^2-z^2-1+2xy-2z)(x^2+y^2-z^2-1-2xy+2z)
1年前
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