一道余数定律的题,大大来下if n is a integer, what is the remainder when 3
一道余数定律的题,大大来下 if n is a integer, what is the remainder when 3x(2^(n+3))-4x(2^(n+2))+5x(2^(n+1))-8 is devided by x+1? 这个n怎么会在这里啊,好纠结,求详解! 不是求n,是求余数,但是这个n怎么消去啊?
if n is a integer,假设n是个整数,求n为何值时 3x(2^(n+3))-4x(2^(n+2))+5x(2^(n+1))-8能被x+1除 即能为何值时 3x(2^(n+3))-4x(2^(n+2))+5x(2^(n+1))-8可以表示为 3x(2^(n+3))-4x(2^(n+2))+5x(2^(n+1))-8 =(x+1)[bx^f(n)+...]