赞 JYH19861101 幼苗
共回答了16个问题采纳率：93.8% 举报
,(X-2-X+2分之5)/ 2x+4分之x-3
=[(x-2)(x+2)-5]/(x+2) ×2(x+2)/(x-3)
=(x²-9) /(x+2)×2(x+2)/(x-3)
=(x+3)(x-3) /(x+2)×2(x+2)/(x-3)
=2(x+3)
=2x+6
=[(x-2)(x+2)-5]/(x+2) ×2(x+2)/(x-3)
=(x²-9) /(x+2)×2(x+2)/(x-3)
=(x+3)(x-3) /(x+2)×2(x+2)/(x-3)
=2(x+3)
=2x+6
1年前
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