计算：[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]

计算：[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]
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jack8158 1年前 已收到3个回答 举报
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yychg 春芽

共回答了18个问题采纳率：94.4% 举报

[(2x+1)/(x²+x-2)]-[(x-2)/(x²-4)]
=(2x+1)/[(x+2)(x-1)]-(x-2)/[(x+2)(x-2)]
=(2x+1)/[(x+2)(x-1)]-1/(x+2)
=(2x+1)/[(x+2)(x-1)]-(x-1)/[(x+2)(x-1)]
=[(2x+1)-(x-1)]/[(x+2)(x-1)]
=(x+2)/[(x+2)(x-1)]
=1/(x-1)

1年前

3

xwy849 花朵

共回答了5510个问题 举报

=(2x+1)/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)(x-1)
=(x+2)/(x+2)(x-1)
=1/(x-1)

1年前

0

xiaobearggfurrylo 果实

共回答了9371个问题 举报

您好：
[（2x+1)/(x²+x-2）]-[（x-2）/（x²-4）]
=（2x+1）/(x+2)(x-1)-(x-2)/(x+2)(x-2)
=(2x+1)/(x+2)(x-1)-1/(x+2)
=(2x+1-x+1)/(x+2)
=(x+2)/(x+2)
=1


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1年前

0
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