赞 domeafavor 幼苗
共回答了19个问题采纳率：89.5% 举报
f(x)
=a.(a-b)
=(sinx,1).(sinx-cosx,3/2)
=(sinx)^2-sinxcosx +3/2
= (1/2)(1-cos2x) -(1/2)sin2x+3/2
=2 -(√2/2)(√2/2)(cos2x+sin2x)
=2- (√2/2)cos(2x-π/4)
max f(x) = 2+√2/2
=a.(a-b)
=(sinx,1).(sinx-cosx,3/2)
=(sinx)^2-sinxcosx +3/2
= (1/2)(1-cos2x) -(1/2)sin2x+3/2
=2 -(√2/2)(√2/2)(cos2x+sin2x)
=2- (√2/2)cos(2x-π/4)
max f(x) = 2+√2/2
1年前
10
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