1/3+1/15+1/35+1/63+1/99=?

zxtc2007 1年前 已收到2个回答 举报

魏勇 幼苗

共回答了17个问题采纳率:88.2% 举报

1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11 1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11 =5/11 1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11 =5/11

1年前

3

zgshine 花朵

共回答了1915个问题 举报

1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11

1年前

0
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