..请帮帮忙55555~1.An electron (charge -1.6×10-19C) moves on a pa

..请帮帮忙55555~
1.An electron (charge -1.6×10-19C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0N/C.How much work is done on the electron as it moves 15 cm?
x05a.4.8×10-20 Jx05b.-4.8×10-20 Jx05c.1.6×10-20 Jx05d.zero
2.A proton (+1.6×10-19C) moves 10cm along the direction of an electric field of strength 3.0N/C.The electrical potential difference between the proton’s initial and ending points is:
x05a.4.8×10-19Vx05b.0.30Vx05x05c.0.033Vx05d.30V
3.A 9.0-V battery is connected between two parallel metal plates 4.0mm apart.What is the magnitude of the electric field between the plates?
x05a.2.3×103N/Cx05b.9.0N/Cx05c.2.3N/Cx05d.0.75×10-6N/C
4.A free electron is in an electric field.With respect to the field,it experiences a force acting:
x05a.parallel.x05x05x05b.anti?parallel(opposite in direction).
x05c.perpendicular.x05x05x05d.along a constant potential line.
5.A uniform electric field,with a magnitude of 600N/C,is directed parallel to the positive x-axis.If the potential at x=3.0m is 1000V,what is the potential at x=1.0m?
x05a.400Vx05x05b.1,600Vx05c.2,200Vx05d.2,500V
6.A uniform electric field,with a magnitude of 600N/C,is directed parallel to the positive x-axis.If the potential at x=3.0m is 1000V,what is the change in potential energy of a proton as it moves from x=3.0m to x=1.0m?(qp=1.6×10-19C)
x05a.8.0×10-17Jx05b.1.9×10-16Jx05c.0.80×10-21Jx05d.500J
7.An electron in a cathode ray tube is accelerated through a potential difference of 5.0kV.What kinetic energy does the electron gain in the process?(e =1.6×10-19C)
x05a.1.6×10-16Jx05b.8.0×10-16Jx05c.1.6×10-22Jx05d.8.0×1022J
8.If the distance between two isolated parallel plates that are oppositely charged is doubled,the electric field between the plates is essentially unchanged.However,the:
x05a.potential difference between the plates will double.
x05b.charge on each plate will double.
x05c.force on a charged particle halfway between the plates will get twice as small.
x05d.force on a charged particle halfway between the plates will get four times as small.
9.An electron is released from rest at the negative plate of a parallel-plate capacitor.If the distance across the plate is 5.0mm and the potential difference across the plate is 5.0V,with what velocity does the electron hit the positive plate?(me=9.1×10-31kg,e =1.6×10-19C)
x05a.2.6×105m/sx05b.5.3×106m/sx05c.1.0×106m/sx05d.1.3×106m/s
10.An electron with velocity v=1.0×106m/s is sent between the plates of a capacitor where the electric field is E=500V/m.If the distance the electron travels through the field is 1.0cm,how far is it deviated(Y) in its path when it emerges from the electric field?(me=9.1×10-31kg,e=1.6×10-19C)
x05a.2.2mmx05b.4.4mmx05c.2.2cmx05x05d.4.4cm