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a = ( A + (A + B)' )'
= A' (A + B) = A'Bb = (B + (A + B)' )' = B' (A + B) = AB'a + b = A'B + AB' = A♁Bc = (C + a + b)' = (C + A♁B)' = C' (A♁B)'F = ((a + b + c)' + (C + c)')' = (a + b + c) (C + c) = (A♁B + C' (A♁B)') (C + C' (A♁B)') = (A♁B + C') (C + (A♁B)') = A♁B C + 0 + 0 + C' A♁B = A♁B1、 A ≠ B 时, F = 12、
1年前
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