6ccc5597qia3n
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[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y)
=[2x²y(x-y) + x²y(y-x)]÷(x²y)
=2(x-y)+(y-x)
=x-y
已知x=2008,y=2004,那么:
原式=x-y=2008-2004=4
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6ccc5597qia3n
[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y) =[2x²y(x-y) + x²y(y-x)]÷(x²y) (中括号的第一项括号内提取xy,第二项括号内提取x) =2(x-y)+(y-x) (由上式分子分母约分得到,约掉的是x²y) =x-y 已知x=2008,y=2004,那么: 原式=x-y=2008-2004=4