wqp258
幼苗
共回答了22个问题采纳率:95.5% 举报
Fe + H2SO4 ==== FeSO4 + H2
Fe___H2
56____2
X___0.1g
X=2.8g
W(Fe)=2.8/3.2*100%=87.5%
2
H2SO4____H2
98____2
X____0.1
X=4.9g
W(H2SO4)=4.9/100 *100%=4.9%
3
FeSO4___H2
152____2
X____0.1
X=7.6g
溶液质量=3.2+100-0.1=103.1
W(FeSO4)=7.6/103.1*100%=7.4%
1年前
6