数学对数涵数运算急

数学对数涵数运算


飞雨的天 1年前 已收到1个回答 举报

sore2003 幼苗

共回答了18个问题采纳率:94.4% 举报

(1)原式=(1/2)*[log2 (7/48)] - (1/2)*(log2 42)+ (log2 12)
=(1/2)*[log2 (7/48) - (log2 42)]+ (log2 12)
=(1/2)*{log2 [(7/48)÷42]} + (log2 12)
=(1/2)*{log2 [1/(6*48)]} + (log2 12)
=-(1/2)*[log2 (4*9*8)] + 2+(log2 3)
=-(1/2)*(5+ log2 9)+ 2+(log2 3)
=(-5/2) - (log2 3)+ 2+(log2 3)
=-1/2
(2)原式=2lg5 + 2lg2+ lg5*(2lg2 + lg5)+(lg2)²
=2+ (lg5)²+2*lg5*lg2+(lg2)²
=2+(lg5+lg2)²
=2+1=3

1年前 追问

9

飞雨的天 举报

  1. =(1/2)*{log2 [1/(6*48)]} + (log2 12)
    =-(1/2)*[log2 (4*9*8)] + 2+(log2 3)这一步怎么变的啊

  • =2+ (lg5)²+2*lg5*lg2+(lg2)²
    还有这里。。呜呜 都不会

举报 sore2003

=(1/2)*{log2 [1/(6*48)]} + (log2 12) =(1/2)*{log2 [(6*48)的-1次幂]} + (log2 12) =-(1/2)*{log2 (6*6*8)} + (log2 12) =-(1/2)*{log2 (4*9*8)} + (log2 12) =-(1/2)*{log2 (3² *2的5次幂)} + (log2 12) 另外: =2+ (lg5)²+2*lg5*lg2+(lg2)² (是指上一步推到这步不会?还是这步推下一步不会哈?)
可能相似的问题
Copyright © 2024 YULUCN.COM - 雨露学习互助 - 17 q. 2.534 s. - webmaster@yulucn.com