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幼苗
共回答了20个问题采纳率:85% 举报
已知:m 1 =21.4g V 1 =16.5cm 3 m 2 =39.9g V 2 =35.0cm 3
求:m 0 =?ρ=?
设量杯的质量为m 0 ,根据题意得:
m 1 - m 0
V 1 =
m 2 - m 0
V 2
代入数值得:
21.4g- m 0
16.5c m 3 =
39.9g- m 0
35.0c m 3
解得:m 0 =4.9g.
则液体的密度: ρ=
m 液
V 液 =
21.4g-4.9g
16.5c m 3 =1g/c m 3 .
答:液体的密度是1g/cm 3 ,量杯的质量是4.9g.
1年前
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