赞 qusitanguan 幼苗
共回答了19个问题采纳率：89.5% 举报
3/x-3 —2/x-2=1/x-1
方程有意义,则x≠3,x≠2,x≠1
3/x-3 —1/x-1=2/x-2
{ 3(x-1) - (x-3) }/{(x-1)(x-3)} = 2/(x-2)
2x /{(x-1)(x-3)} = 2/(x-2)
x /{(x-1)(x-3)} = 1/(x-2)
x(x-2) = (x-1)(x-3)
x^2-2x = x^2-4x+3
2x=3
x=3/2
方程有意义,则x≠3,x≠2,x≠1
3/x-3 —1/x-1=2/x-2
{ 3(x-1) - (x-3) }/{(x-1)(x-3)} = 2/(x-2)
2x /{(x-1)(x-3)} = 2/(x-2)
x /{(x-1)(x-3)} = 1/(x-2)
x(x-2) = (x-1)(x-3)
x^2-2x = x^2-4x+3
2x=3
x=3/2
1年前
10
共回答了3685个问题 举报
3/x-3 —2/x-2=1/x-1
3(x-1)(x-2)-2(x-1)(x-3)-(x-2)(x-3)=0
3x^2-9x+6-2x^2+8x-6-x^2+5x-6=0
4x=6
x=1.5
3(x-1)(x-2)-2(x-1)(x-3)-(x-2)(x-3)=0
3x^2-9x+6-2x^2+8x-6-x^2+5x-6=0
4x=6
x=1.5
1年前
0
你能帮帮他们吗