幽幽谷幽幽
幼苗
共回答了18个问题采纳率:94.4% 举报
y=[10^x+10^(-x)]/[10^x-10^(-x)]+2
y-2=[(10^x)^2+1]/[(10^x)^2-1]
(y-2)[(10^x)^2-1]=(10^x)^2+1
(y-3)*(10^x)^2=1+y-2
(10^x)^2=(y-1)/(y-3)
10^x=√[(y-1)/(y-3)]
x=lg √[(y-1)/(y-3)]
反函数:y=lg √[(x-1)/(x-3)]
(x-1)/(x-3)>0
x3
1年前
追问
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