qinzhi1226
幼苗
共回答了13个问题采纳率:84.6% 举报
f(x)=(√3/2)2sinx/2cox/2+cos^2(x/2)+m 【原题中,cos^2(x/3),恐是把2误打成3了,应该是cos^2(x/2)吧】.
=√3/2sinx+(1/2)cosx+1/2+m.
∴f(x)=sin(x+π/6)+1/2+m.
f(5π/6)=sin(5π/6+π/6)+1/2+m=0.
sinπ+1/2+m=0.
0+1/2+m=0.
∴m=-1/2.
∵sinx的单调增区间为x∈[2kπ-π/2,2kπ+π/2],k∈Z,
∴sin(x+π/6的单调增区间是:x+π/6∈[2kπ-π/3,2kπ+2π/3]k∈Z.
1年前
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