wsj45481844
幼苗
共回答了18个问题采纳率:88.9% 举报
1/4{a^2b^2-[(a^2+b^2-c^2)/2]^2}
=1/4[ab+(a^2+b^2-c^2)/2][ab-(a^2+b^2-c^2)/2]
=1/16[(a^2+b^2+2ab)-c^2)[c^2-(a^2-2ab+b^2)]
=1/16*[(a+b)^2-c^2][c^2-(a-b)^2]
=1/16*(a+b+c)(a+b-c)(c+a-b)(c-a+b)
=[(a+b+c)/2]{[(a+b+c)/2-c]/2}{[(a+b+c)/2-b]/2}{[(a+b+c)/2-a]/2}
=p(p-c)(p-b)(p-a)
1年前
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