198312050931
幼苗
共回答了19个问题采纳率:100% 举报
[1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)]>[1/(10x11)+1/(11x12)+1/(12x13)+.+1(1000x1001)]=(1/10)-(1/11)+(1/11)-(1/12)+.+(1/1000)-(1/1001)=(1/10)-(1/1001)=0.099[1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)]
1年前
6